Ajax will not donate as much money to the other teams in the league

first_imgThe humanitarian crisis that the planet is experiencing is historical and undoubtedly the most important, but the consequences will also be seen – and are already being seen – in the economic sphere. It will be a difficult time and organizations are improvising measures so that the damage is as small as possible. One of the ideas of the KNVB, the Dutch soccer federation, is for the clubs to distribute their revenue from European competitions this season to the other clubs in the league out of “moral obligation”. Especially and being the one that receives the most money, Ajax.The clubs are already obliged to distribute a small percentage of this UEFA money for the development of football in the country. In the case of Ajax, he already pays 2.6 million to the Eredivisie and also has always been in favor of helping in a common emergency fund of the league. However, and as reported by some local media this morning, Now the Amsterdam club is not there to give away money and will not contribute to that proposal as much as the KNVB wants. Ajax is the team that will receive the most from UEFA in the Netherlands, but also the one that will lose the most due to the coronavirus crisis. It is estimated that he could stop earning more than 50 million euros for a season behind closed doors. One of the AZ proposals is to donate 25%, something that does not even occur to the management of Van der Sar. They are in favor of donating money: “It stands to reason that as the largest club in the country, we help other clubs survive”, explained the exporter. But you also know that Ajax “He will have a difficult time.”That 25% of the talk could add more than the accumulated between AZ Alkmaar (previous to the Champions League), Feyenoord (Europa League) and PSV and Willem II (previous to the Europa League). Obviously, it seems somewhat excessive for a club that will suffer more than any other from this economic crisis. They will donate, but not everything they ask for.last_img

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